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a 7.500-mg sample of chromium-55 is analyzed after 14.0 min and found to contain 0.469 mg of chromium-55. what is the half-life of chromium-55

  • chemistry -

    ln(No/N) = kt
    Substitute No = 7.500 mg
    N = 0.469 mg
    t = 14 min
    Solve for k. Then substitute k into the following.
    k = 0.693/t1/2 and solve for t1/2

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