Monday
March 27, 2017

Post a New Question

Posted by on .

a 7.500-mg sample of chromium-55 is analyzed after 14.0 min and found to contain 0.469 mg of chromium-55. what is the half-life of chromium-55

  • chemistry - ,

    ln(No/N) = kt
    Substitute No = 7.500 mg
    N = 0.469 mg
    t = 14 min
    Solve for k. Then substitute k into the following.
    k = 0.693/t1/2 and solve for t1/2

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question