Posted by Natasha on Wednesday, February 8, 2012 at 6:20pm.
Vo = 16m/s @ 47 Deg.
Xo = 16*cos47 = 10.91 m/s.
Yo = 16*sin47 = 11.70 m/s.
Tr = (Yf-Yo)/g,
Tr = (0-11.70) / -9.8 = 1.19 s. = Time
to rise to max ht.
hmax = (Yf^2-Yo^2)/2g.
hmax = (0-(11.70)^2) / -19.6 = 6.98 m.
= Max ht above launching point.
d = Vo*t + 0.5g*t^2 = 6.98-2.10,
0 + 4.9t^2 = 4.88,
t^2 = 0.996,
Tf = 1.0 s. = Time to fall to 2.10 m
above launching point.
Dx = Xo(Tr+Tf) = 10.91(2.19) = 23.9 m.
= Hor. dist. of ball.
d = 0.5a*t^2 = (23.9-10) m,
0.5a*(2.19-0.30)^2 = 13.9,
0.5a*3.57 = 13.9,
1.786a = 13.9,
a = 13.9 / 1.786 = 7.78 m/s^2. = acceleration of player.
V = at = 7.78*(2.19-0.30) = 14.7 m/s. =
Speed of plaver.
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