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December 22, 2014

December 22, 2014

Posted by **ameyo** on Wednesday, February 8, 2012 at 5:16pm.

- charle drew high -
**MathMate**, Wednesday, February 8, 2012 at 5:28pmThe probability of an odd number (1,3 or 5) on the first roll is 3/6=1/2

For the second roll, to get a multiple of three (3 or 6) the probability is 2/6=1/3

The two rolls are independent.

So the probability of succeeding both events is (1/2)*(1/3)=1/6

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