Posted by **LK** on Wednesday, February 8, 2012 at 4:44pm.

A car accelerates from rest at a steady rate of 1 ms-2. Calculate:

(a) the time taken to reach 15 ms-1

(b) the distance travelled during this time

(c) the velocity of the car when it was 100 m from the start point

- physics -
**Elena**, Wednesday, February 8, 2012 at 5:31pm
1.

For accelerated motion

s=v0t+(at2/2) and v=v0 + at

Since initial velocity v0 is zero,

s=at2/2 and v= at.

t=v/a=15/1=15 s.

s=1•225/2=112.5 m.

2.

If s =at2/2 = 100 m,

t=sqroot(2s/a)= sqroot(2•100/1)=14.14 s.

v=at=1•14.14=14.14 m/s.

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