Post a New Question

physics

posted by on .

A car accelerates from rest at a steady rate of 1 ms-2. Calculate:
(a) the time taken to reach 15 ms-1
(b) the distance travelled during this time
(c) the velocity of the car when it was 100 m from the start point

  • physics - ,

    a. V = at = 15 m/s.
    1*t = 15,
    t = 15 s.

    b. d = 0.5a*t^2,
    d = 0.5*(15)^2 = 112.5 m.

    c. V^2 = Vo^2 + 2a*d,
    V^2 = 0 + 2*100 = 200,
    V = 14.14 m/s.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question