Posted by **Anonymous** on Wednesday, February 8, 2012 at 2:38pm.

While an elevator of mass 2681 kg moves upward, the tension in the cable is 29.4 kN.

(a) What is the acceleration of the elevator?

(b) If at some point in the motion the velocity of the elevator is 1.04 m/s upward, what is the elevator's velocity 3.96 s later?

Please helppp and explain because I keep getting it wrong!!! Thnks

- Physics -
**bobpursley**, Wednesday, February 8, 2012 at 2:43pm
tension= (mg+ma) solve for a.

b. Vnext= vfirst+ a t

solve for vnext

- Physics -
**Anonymous**, Wednesday, February 8, 2012 at 2:47pm
So would it be

29.4=(2681(9.8)+2681(a))

I don't think so cuz it gives me .001 n thtz wrong...

- Physics -
**bobpursley**, Wednesday, February 8, 2012 at 2:50pm
You need a tutor. Tension=ma+mg is in SI units. Tension was given as 29,400 Newtons.

You have to consider units.

- Physics -
**Anonymous**, Wednesday, February 8, 2012 at 2:52pm
Oh I see...thnk you n sorry :/

- Physics -
**Anonymous**, Wednesday, February 8, 2012 at 3:00pm
would the be a=-6.8 or 6.8 ???

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