Posted by helen on Wednesday, February 8, 2012 at 1:07pm.
moles KOH = M x L = ?
moles HCl = M x L = ?
All K^+ come from KOH. All Cl^- come from HCl.
a. (K^+) = moles K^/L soln
b. (Cl^-) = moles Cl^-/L soln.
c. KOH + HCl ==> KCl + H2O
(H^+) or (OH^-) is determined by which reagent is in excess. Subtract the moles and see which is in excess and convert to pH or pOH.
Post your work if you get stuck.
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