Posted by **Rick** on Wednesday, February 8, 2012 at 11:58am.

Here is the math problem:

The height of an object in free fall, or otherwise thrown into the air near the earth's surface, with initial vertical velocity v0 in feet per seconds, and from the initial height h0 in feet, at any given time t in seconds is given by the equation:

h(t)= -16t^2 + v0t + h0

At 1821 feet tall, the CN Tower in Toronto, Canada is the world's tallest...etc. Suppose an object is dropped from the top of the tower (just released not pushed) .

1. The equation above find h0 and v0

2. The height of the object 2.3 seconds after being released.

Please help, even if you could show me how to proper start this problem I would be thankful! :]

## Answer This Question

## Related Questions

- Calculus - Falling Body Problem - Near the surface of the earth, the ...
- math - using this information: if an object is thrown straight up into the air ...
- math - using this information: if an object is thrown straight up into the air ...
- math. can someone explain this! - using this information: if an object is thrown...
- Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...
- Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...
- math - An object that is falling or vertically projected into the air has it ...
- algebra - An object is released into the air at an initial height of 6 feet and ...
- college physics - An object thrown vertically upward with initial velocity from ...
- algebra - 5. 16t2 gives the distance in feet a free-falling object falls in t ...

More Related Questions