CALC 2A
posted by Student (UCI) on .
True or False. If f is continuous at 5 and f(5)=2 and f(4)=3,
the the lim x> 2 f(4x^211) = 2
the answer is true, but i do not understand why..because when i plug the numbers in im not getting what it has stated. Please explain thanks:)

When x = 2, 4x^211 = 5
You have been told that f(x) is continuous at x = 5, and that the value of f(5) = 2.
Therefore the answer is true.
The question is a bit confusing because you have to think of 4x^211 as the argument of the f(x) function. 
Thanks that makes much more sense:)