Posted by Student (UCI) on Tuesday, February 7, 2012 at 9:24pm.
True or False. If f is continuous at 5 and f(5)=2 and f(4)=3,
the the lim x> 2 f(4x^211) = 2
the answer is true, but i do not understand why..because when i plug the numbers in im not getting what it has stated. Please explain thanks:)

CALC 2A  drwls, Tuesday, February 7, 2012 at 10:07pm
When x = 2, 4x^211 = 5
You have been told that f(x) is continuous at x = 5, and that the value of f(5) = 2.
Therefore the answer is true.
The question is a bit confusing because you have to think of 4x^211 as the argument of the f(x) function. 
CALC 2A  Student (UCI), Wednesday, February 8, 2012 at 11:22am
Thanks that makes much more sense:)