Posted by ann on Tuesday, February 7, 2012 at 5:16pm.
please check and correct thanks
Problem: solve and check the inequality if possible
4F+8< 12
positive: negative:
4F+8 < 12 4F + 8 < 12
4F + 8 8 < 12  8 4F +88 < 128
4F < 4 4F< 20
F < 1 F< 5
solutions 1 and 5 or
5 < F < 1
check positive ck negative
4F + 8 < 12 4F + 8 < 12
4(1) + 8 < 12
4 + 8 < 12 4(5) + 8 < 12
12 < 12 20 +8 < 12
12 < 12

algebra  Reiny, Tuesday, February 7, 2012 at 6:31pm
Easier way:
4F + 8 < 12 AND 4F  8 < 12
4F < 4 AND 4F < 20
F < 1 AND F > 5
so, ....
5 < F < 1
(your check should include a value for each of the 3 regions , that is
F < 1
F between 1 and 5
F > 5

algebra  ann, Wednesday, February 8, 2012 at 4:33am
thank you so much for your help reiny. ann
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