Wednesday

August 27, 2014

August 27, 2014

Posted by **ann** on Tuesday, February 7, 2012 at 5:16pm.

Problem: solve and check the inequality if possible

|4F+8|< 12

positive: negative:

|4F+8| < 12 |4F + 8| < -12

4F + 8 -8 < 12 - 8 4F +8-8 < -12-8

4F < 4 4F< -20

F < 1 F< -5

solutions 1 and -5 or

-5 < F < 1

check positive ck negative

|4F + 8| < 12 |4F + 8| < -12

4(1) + 8 < 12

4 + 8 < 12 4(-5) + 8 < -12

12 < 12 -20 +8 < -12

-12 < -12

- algebra -
**Reiny**, Tuesday, February 7, 2012 at 6:31pmEasier way:

4F + 8 < 12 AND -4F - 8 < 12

4F < 4 AND -4F < 20

F < 1 AND F > -5

so, ....

-5 < F < 1

(your check should include a value for each of the 3 regions , that is

F < -1

F between -1 and 5

F > 5

- algebra -
**ann**, Wednesday, February 8, 2012 at 4:33amthank you so much for your help reiny. ann

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