The density of liquid "A" is 1.80gm/ml, liquid "B" is 1.10 gm/ml and liquid "C" is 1.40 gm/ml. If theses liquids are immiscible in each other and a piece of solid with a specific gravity of 0.80 is placed in a container of all these liquids, what will happen?
0.80 on top
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liquid with d = 1.1
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liquid with d = 1.40
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liquid with d = 1.80
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container
To understand what will happen when a piece of solid with a specific gravity of 0.80 is placed in containers of liquids A, B, and C, we need to consider their respective densities.
Density is defined as the mass of a substance per unit volume. In simple terms, it measures how tightly packed the molecules of a substance are.
Comparing the density of the solid to the densities of the liquids, we can infer the following:
1. The specific gravity of the solid (0.80) indicates that it is less dense than water (1.00 gm/mL). This means the solid will float on water.
2. The density of liquid A (1.80 gm/mL) is higher than the density of the solid (0.80 gm/mL). As a result, the solid will float on liquid A.
3. The density of liquid B (1.10 gm/mL) is lower than the density of the solid (0.80 gm/mL). Consequently, the solid will also float on liquid B.
4. The density of liquid C (1.40 gm/mL) is higher than the density of the solid (0.80 gm/mL). Therefore, the solid will float on liquid C as well.
Based on the fact that the solid has a lower density than all the liquids, it will float on top of the liquids A, B, and C. Since the liquids are immiscible (unmixable) with each other, they will form separate layers in the container, with the solid floating on top of each liquid layer.