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August 31, 2015

Homework Help: Calculus

Posted by Emily on Tuesday, February 7, 2012 at 1:20am.

uu) lim ln(1-x) as x->1-

yy) lim (√(6-x)-2)/(√(3-x)-1) as x-> 2

zz) lim (1-(1/2)arctanx) as x->-∞

bbb) lim ln|1-x| as x->1

If these are hard to interpret with all the parentheses, you can plug them in to Wolfram Alpha and it interprets them perfectly.

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