Posted by **Emily** on Tuesday, February 7, 2012 at 1:20am.

uu) lim ln(1-x) as x->1-

yy) lim (√(6-x)-2)/(√(3-x)-1) as x-> 2

zz) lim (1-(1/2)arctanx) as x->-∞

bbb) lim ln|1-x| as x->1

If these are hard to interpret with all the parentheses, you can plug them in to Wolfram Alpha and it interprets them perfectly.

- Calculus -
**Emily**, Tuesday, February 7, 2012 at 1:22am
Sorry, I forgot one:

w) lim (1-2cos^2x)/(cosx-sinx) as x->π/4

- Calculus -
**Anonymous**, Tuesday, February 7, 2012 at 5:28am
if you've already been to wolfram, and it shows steps as needed, why bother posting here?

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