Posted by Emily on Tuesday, February 7, 2012 at 1:20am.
uu) lim ln(1x) as x>1
yy) lim (√(6x)2)/(√(3x)1) as x> 2
zz) lim (1(1/2)arctanx) as x>∞
bbb) lim ln1x as x>1
If these are hard to interpret with all the parentheses, you can plug them in to Wolfram Alpha and it interprets them perfectly.

Calculus  Emily, Tuesday, February 7, 2012 at 1:22am
Sorry, I forgot one:
w) lim (12cos^2x)/(cosxsinx) as x>π/4

Calculus  Anonymous, Tuesday, February 7, 2012 at 5:28am
if you've already been to wolfram, and it shows steps as needed, why bother posting here?
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