Posted by Chloe on .
A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 8.15 m/s at an angle of 18.5o below the horizontal. It strikes the ground 3.30 s later. How far horizontally from the base of the building does the ball strike the ground?
What heigh was the ball thrown from?
Vo = 8.15 m/s @ 18.5 Deg.,down.
Xo = 8.15*cos18.5 = 7.73 m/s.
Yo = 8.15*sin18.5 = 2.59 m/s.
a. Tf = 3.30 s. = Fall time or time in
Dx=Xo * Tf = 7.73m/s * 3.30s = 25.5 m.=
Hor. dist. from base of bldg.
b. h = Yo*t + 0.5g*t^2,
h = 2.59*3.30 + 4.9*(3.3)^2 = 61.9 m.