Sunday

October 26, 2014

October 26, 2014

Posted by **Keya** on Monday, February 6, 2012 at 7:41pm.

- Calculus -
**Reiny**, Monday, February 6, 2012 at 9:42pmMaking a sketch for the 12 noon position, placing B at the origin and A 65 units up on the y-axis

At a time of t hrs after noon,

let the distance covered by A be 14t

let the distance covered by B be 16t

Draw a line between their positions and call it d km

d^2 = (16t)^2 + (65-14t)^2

when t = 1.5

d^2 = 620

d = √620

2d dd/dt = 2(16t)(16) + 2(65- 14t)(14)

dd/dt = (256t + 65 - 196t)/√620

when t=1.5

dd/dt = (256(1.5) + 65 - 196(1.5))/√620

= 6.22 km/h

check my arithmetic

**Answer this Question**

**Related Questions**

math - at 12 noon ship A is 65 km due north of a second ship B. Ship A sails ...

engineering science N4 - Two ships leave port simultaneously. Ship A sails north...

Calculus - One ship is 20 miles due North of another ship, and is sailing South ...

Calculus - 1.At noon of a certain day,ship A is ^0 km due north of ship B. If A ...

calculus - At 1:00 p.m. ship A is 25 km due north of ship B. If ship A is ...

Calculus - At 1:00 p.m. ship A is 25 km due north of ship B. If ship A is ...

Trigonometry - Navigation A ship leaves port at noon and has a bearing of S 29° ...

Trig - A ship leaves its homeport and sails on a bearing of N28degrees10'E. ...

Calculus - Two ships leave the same port at noon. Ship A sails north at 22 mph, ...

Calculus 1 - Related Rates I am having trouble finding the equation to use to ...