Posted by **Keya** on Monday, February 6, 2012 at 7:41pm.

at 12 noon ship A is 65 km due north of a second ship B. Ship A sails south at a rate of 14km/hr, and ship B sails west at a rate of 16km/hr. How fast are the two ships approaching each other 1.5 hours later at 1:30pm? Thank You!

- Calculus -
**Reiny**, Monday, February 6, 2012 at 9:42pm
Making a sketch for the 12 noon position, placing B at the origin and A 65 units up on the y-axis

At a time of t hrs after noon,

let the distance covered by A be 14t

let the distance covered by B be 16t

Draw a line between their positions and call it d km

d^2 = (16t)^2 + (65-14t)^2

when t = 1.5

d^2 = 620

d = √620

2d dd/dt = 2(16t)(16) + 2(65- 14t)(14)

dd/dt = (256t + 65 - 196t)/√620

when t=1.5

dd/dt = (256(1.5) + 65 - 196(1.5))/√620

= 6.22 km/h

check my arithmetic

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