Posted by Steve on Monday, February 6, 2012 at 3:49pm.
a. 100 kg H2O from 22 to 100 will require how much energy?
That is mass H2O (in grams) x specific heat H2O (J/g*C) x (100-22) = ?J
oil needed(lbs) = 1 lb x (?J/2.4E7)
Convert lbs oil to kg.
b. Same concept but heat needed is
100,000 g H2O x delta Hvap = heat needed.
Related Questions
Physics - Given that electricity is priced at constant 13.5 pence per kWh and ...
Physics - A steam engine's boiler completely converts 155 kg of water to ...
Integrated Physics and Chemistry - Matching... Heat engine Heat pump Boiler ...
Thermodynamics - Design Problem- A steam boiler may be thought of as a heat ...
Thermodynamics - Design Problem- A steam boiler may be thought of as a heat ...
Integrated Physics and Chemistry - A thermostat is used for which of the ...
Economics - Suppose the price elasticity of demand for heating oil is 0.2 in the...
chemistry - In industrial plants, what specific type of oil is used as heating ...
Chemistry - In industrial plants, what specific type of oil is used as heating ...
Chemistry Help!! - Propane(C3H8), the major component of LP game, is often used ...
For Further Reading