Calculate the mL of 2.00 M H2SO4 required to neutralize 50.0 mL of 1.00 M KOH?
consider that H2SO4 has two acidic hydoregens
H2SO4(aq) +2KOH(aq)---->K2SO4(aq) + 2H2O(l)
Ah, the classic chemistry question. Now, let me put on my humor goggles to give you a funny answer.
Well, you've got 2.00 M H2SO4 and 1.00 M KOH having a party. It's like a chemistry rave, with acids and bases bouncing around. But we need to neutralize 50.0 mL of KOH with H2SO4.
So, let's do some math-rave moves. Since H2SO4 has two acidic hydrogen, it needs twice the number of KOH. It's like bringing two dates to a party.
The balanced equation tells us that it takes 2 moles of KOH to react with 1 mole of H2SO4, so we need to use some stoichiometry (fancy word alert).
First, we calculate the moles of KOH in 50.0 mL (0.050 L):
0.050 L * 1.00 mol/L = 0.050 mol
Since we need two moles of KOH for every mole of H2SO4, we divide by 2:
0.050 mol / 2 = 0.025 mol
Finally, we need to find the volume of 2.00 M H2SO4 (let's call it Party Punch) that corresponds to 0.025 moles.
0.025 mol * (1 L / 2.00 mol) = 0.0125 L
Converting it to milliliters (because chemistry loves metric units):
0.0125 L * 1000 mL/L = 12.5 mL
So, pour yourself a 12.5 mL glass of H2SO4 Party Punch, and you'll have a neutralization party like no other. Cheers! 🥳
To calculate the volume of 2.00 M H2SO4 required to neutralize 50.0 mL of 1.00 M KOH, you need to determine the stoichiometric ratio between H2SO4 and KOH.
From the balanced chemical equation:
H2SO4(aq) + 2KOH(aq) → K2SO4(aq) + 2H2O(l)
You can see that for every one mole of H2SO4, you need 2 moles of KOH to complete the reaction.
First, calculate the number of moles of KOH present in 50.0 mL of 1.00 M KOH using the formula:
Moles = Volume (in liters) x Concentration (in M)
Given:
Volume of KOH = 50.0 mL = 50.0/1000 L = 0.05 L
Concentration of KOH = 1.00 M
Moles of KOH = 0.05 L x 1.00 M = 0.05 moles
Since the stoichiometric ratio is 1:2 between H2SO4 and KOH, you would need twice the number of moles of H2SO4 to neutralize the KOH.
Therefore, the number of moles of H2SO4 needed = 2 x 0.05 moles = 0.10 moles
Finally, calculate the volume of 2.00 M H2SO4 required to provide 0.10 moles of H2SO4 using the formula:
Volume (in liters) = Moles / Concentration (in M)
Given:
Moles of H2SO4 = 0.10 moles
Concentration of H2SO4 = 2.00 M
Volume of H2SO4 = 0.10 moles / 2.00 M = 0.05 L
However, the volume is currently in liters. Convert it to milliliters by multiplying by 1000:
Volume of H2SO4 = 0.05 L x 1000 mL/L = 50.0 mL
Therefore, 50.0 mL of 2.00 M H2SO4 is required to neutralize 50.0 mL of 1.00 M KOH.
To calculate the milliliters (mL) of 2.00 M H2SO4 required to neutralize 50.0 mL of 1.00 M KOH, you need to use the balanced equation and the concept of stoichiometry.
The balanced equation is:
H2SO4(aq) + 2KOH(aq) → K2SO4(aq) + 2H2O(l)
From the equation, you can see that one mole of H2SO4 reacts with two moles of KOH. This means that the stoichiometric ratio between H2SO4 and KOH is 1:2.
First, we need to calculate the number of moles of KOH in 50.0 mL of 1.00 M KOH:
moles of KOH = volume of KOH (in liters) × molarity of KOH
moles of KOH = 50.0 mL / 1000 mL/L × 1.00 mol/L
moles of KOH = 0.050 mol
Since the stoichiometric ratio is 1:2 for H2SO4 and KOH, the number of moles of H2SO4 required to neutralize the given amount of KOH is the same, which is 0.050 mol.
Now, we can calculate the volume of 2.00 M H2SO4 required to neutralize 0.050 mol of H2SO4:
volume of H2SO4 (in liters) = moles of H2SO4 / molarity of H2SO4
volume of H2SO4 (in liters) = 0.050 mol / 2.00 mol/L
volume of H2SO4 (in liters) = 0.025 L
Finally, to convert the volume from liters to milliliters:
volume of H2SO4 (in mL) = volume of H2SO4 (in liters) × 1000 mL/L
volume of H2SO4 (in mL) = 0.025 L × 1000 mL/L
volume of H2SO4 (in mL) = 25.0 mL
Therefore, 25.0 mL of 2.00 M H2SO4 is required to neutralize 50.0 mL of 1.00 M KOH.
moles KOH = M x L = ?
Convert moles KOH to moles H2SO4 using the coefficients in the balanced equation.
?mol KOH x (1 mole H2SO4/2 moles KOH) =
? mol KOH x (1/2) = x mol H2SO4
Now, M H2SO4 = moles H2SO4/L H2SO4.
You know M H2SO4 and moles H2SO4, solvwe for L H2SO4 and convert to mL.