Posted by April on .
Calculate the mL of 2.00 M H2SO4 required to neutralize 50.0 mL of 1.00 M KOH?
consider that H2SO4 has two acidic hydoregens
H2SO4(aq) +2KOH(aq)---->K2SO4(aq) + 2H2O(l)
moles KOH = M x L = ?
Convert moles KOH to moles H2SO4 using the coefficients in the balanced equation.
?mol KOH x (1 mole H2SO4/2 moles KOH) =
? mol KOH x (1/2) = x mol H2SO4
Now, M H2SO4 = moles H2SO4/L H2SO4.
You know M H2SO4 and moles H2SO4, solvwe for L H2SO4 and convert to mL.