Balance the following chemical equation:
C3H7OH(l) + O2(g) CO2(g) + H2O(g)
2C3H7OH + 9O2 >> 6CO2+8H2O
To balance the chemical equation C3H7OH(l) + O2(g) -> CO2(g) + H2O(g), you need to ensure that there is an equal number of atoms on both sides of the equation. Follow these steps to balance the equation:
Step 1: Count the number of carbon atoms on both sides.
On the left side: 1 carbon atom (C3H7OH)
On the right side: 1 carbon atom (CO2)
Step 2: Count the number of hydrogen atoms on both sides.
On the left side: 7 hydrogen atoms (C3H7OH)
On the right side: 2 hydrogen atoms (H2O)
Step 3: Count the number of oxygen atoms on both sides.
On the left side: 2 oxygen atoms (C3H7OH)
On the right side: 2 oxygen atoms (CO2) + 1 oxygen atom (H2O) = 3 oxygen atoms
Step 4: To balance the carbon atoms, put a coefficient of 3 in front of CO2 on the right side.
C3H7OH(l) + O2(g) -> 3CO2(g) + H2O(g)
Step 5: To balance the hydrogen atoms, put a coefficient of 4 in front of H2O on the right side.
C3H7OH(l) + O2(g) -> 3CO2(g) + 4H2O(g)
Step 6: To balance the oxygen atoms, put a coefficient of 5/2 (or 2.5) in front of O2 on the left side.
2.5(C3H7OH(l)) + O2(g) -> 3CO2(g) + 4H2O(g)
Note that in order to balance the equation, it is acceptable to use fractions as coefficients.
The final balanced chemical equation is:
2.5(C3H7OH(l)) + O2(g) -> 3CO2(g) + 4H2O(g)
To balance the equation, you need to make sure that the number of atoms on both sides of the chemical equation is the same.
Here's how you can balance the given chemical equation:
1. Start by counting the number of each type of atom on both sides of the equation.
Left Side (Reactants):
- Carbon (C): 3
- Hydrogen (H): 8 (3 from C3H7OH and 5 from H2O)
- Oxygen (O): 1 (from C3H7OH)
Right Side (Products):
- Carbon (C): 1 (from CO2)
- Hydrogen (H): 2 (from H2O)
- Oxygen (O): 4 (2 from CO2 and 2 from O2)
2. Balance the carbon atoms.
Since there are 3 carbon atoms on the left side and only 1 carbon atom on the right side, you need to multiply CO2 by 3 to balance the carbons:
C3H7OH(l) + O2(g) 3CO2(g) + H2O(g)
3. Balance the hydrogen atoms.
There are 8 hydrogen atoms on the left side and only 2 hydrogen atoms on the right side, so you need to multiply H2O by 4 to balance the hydrogens:
C3H7OH(l) + O2(g) 3CO2(g) + 4H2O(g)
4. Balance the oxygen atoms.
There is 1 oxygen atom on the left side and 8 oxygen atoms on the right side. To balance the oxygens, you can now calculate the total number of oxygen atoms on the left side and subtract it from the total number of oxygen atoms on the right side:
3(2) + 4 = 10
To balance the oxygens, you need to add O2 to the left side with a coefficient of 5:
C3H7OH(l) + 5O2(g) 3CO2(g) + 4H2O(g)
Now, both sides of the equation have 3 carbon atoms, 8 hydrogen atoms, and 10 oxygen atoms, and the equation is balanced.
C3H7OH + O2 >> CO2 + H2O
start with the most complicated formula, the leftmost.
C3H7OH+ O2 >> 3CO2 + H2O
then the H
C3H7OH+ O2 >> 3CO2 + 4H2O
then the O. Start on the right, since you don't want to mess with those coefficents. You have 10 O
C3H7OH + 5O2>>3CO2 + 4H2O Notice it does not balance because of the OH.
So, go back and double the C3H7OH.
2C3H7OH+ O2 >> 6CO2 + 8H2O
2C3H7OH+ 6O2>> 3CO2+8H2O
check that