Posted by Emily on .
An open tube of length L = 1.60 m and crosssectional area A = 4.60 cm2 is fixed to the top of a cylindrical barrel of diameter D = 1.27 m and height H = 2.16 m. The barrel and tube are filled with water (to the top of the tube). Calculate the ratio of the hydrostatic force on the bottom of the barrel to the gravitational force on the water contained in the barrel. (You need not consider the atmospheric pressure.)

Physics 
bobpursley,
gravitational force=mg=volumebarrel*density*g
=H*(D/2)^2*PI*density*g
hydrostatic force= (H+1.60)4.6E4*density*g this is the force on the column of water at the bottom. But due to Pascal's principle, that force is multiplied by the area of the barrel, so
hydrostaticForce=(2,16+1.60)4.6E4*(1.27)^2/4.6E4
check all that. 
Physics 
Anonymous,
I'm confused as to how you're getting 4.6*10^4.. the answer i get isn't working.

Physics 
Anonymous,
Never mind...I get it now..it was just a change in units. But my answer is still not correct.