Posted by **Emily** on Monday, February 6, 2012 at 8:33am.

An open tube of length L = 1.60 m and cross-sectional area A = 4.60 cm2 is fixed to the top of a cylindrical barrel of diameter D = 1.27 m and height H = 2.16 m. The barrel and tube are filled with water (to the top of the tube). Calculate the ratio of the hydrostatic force on the bottom of the barrel to the gravitational force on the water contained in the barrel. (You need not consider the atmospheric pressure.)

- Physics -
**bobpursley**, Monday, February 6, 2012 at 9:01am
gravitational force=mg=volumebarrel*density*g

=H*(D/2)^2*PI*density*g

hydrostatic force= (H+1.60)4.6E-4*density*g this is the force on the column of water at the bottom. But due to Pascal's principle, that force is multiplied by the area of the barrel, so

hydrostaticForce=(2,16+1.60)4.6E-4*(1.27)^2/4.6E-4

check all that.

- Physics -
**Anonymous**, Monday, February 6, 2012 at 12:27pm
I'm confused as to how you're getting 4.6*10^4.. the answer i get isn't working.

- Physics -
**Anonymous**, Monday, February 6, 2012 at 12:28pm
Never mind...I get it now..it was just a change in units. But my answer is still not correct.

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