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October 31, 2014

October 31, 2014

Posted by **MJ** on Monday, February 6, 2012 at 7:45am.

- algebra -
**Reiny**, Monday, February 6, 2012 at 9:23amnumber of pens for Bob --- x

number of pens for Jane --- y

case1: Bob gives 3 pens to Jane

Bob has x-3

Jane has y+3

so x-3 = y+3

x-y = 6

case2: Jane gives 3 pens

Bob has x+3

Jane has y-3

x+3 = 3(y-3)

x+3 = 3y - 9

x - 3y = -12

subtract the two equations

2y = 18

y = 9

sub into 1st equation:

x-9 = 6

x = 15

Bob now has 15 and Jane has 9

after 1st transfer, bob has 12 and Jane has 12, good!

afer 2nd transfer, Bob has 18 and Jane has 6

does he have 3 times what she has? YES!

all is good!

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