Sum of two numbers is 95. one number exceeds the other by 15,find the number?
a = first number
b = second number
b = 15 + a
a + b = 95
a + 15 + a = 95
2 a + 15 = 95
2 a = 95 - 15
2 a = 80 Diwide both sides by 2
a = 80 / 2
a = 40
b = 15 + a
b = 15 + 40
b = 55
a + b = 40 + 55 = 95
Dennis
Good
To solve this problem, let's assume the smaller number as "x" and the larger number as "x + 15".
We know that the sum of the two numbers is 95. Therefore, we can write the equation as:
x + (x + 15) = 95
Now, let's simplify the equation:
2x + 15 = 95
Next, we'll isolate the variable x by subtracting 15 from both sides of the equation:
2x = 95 - 15
2x = 80
Finally, we'll solve for x by dividing both sides of the equation by 2:
x = 80 / 2
x = 40
So the smaller number is 40, and the larger number is 40 + 15 = 55.