Magnesium hydroxide + hydrogen chloride-----> magnesium chloride + water
How many grams of magnesium chloride can be produced from 14.60 mL of a 0.546M hydrogen chloride solution?
moles HCl=.0146*.546
balance the equation
Mg(OH)2 + 2HCl>>MgCl2 + 2H2O
so you get 1/2 that number of moles of magnesium chloride. Convert that to grams.
To calculate the grams of magnesium chloride produced, we need to first calculate the amount of moles of hydrogen chloride (HCl) present in the solution, and then use the balanced equation to determine the moles of magnesium chloride (MgCl2) produced. Finally, we can convert the moles of MgCl2 to grams using the molar mass of MgCl2.
Step 1: Calculate the moles of HCl
To calculate the moles of HCl, we will use the formula: moles = concentration (M) x volume (L)
Given:
- Volume of HCl solution = 14.60 mL
- Concentration of HCl solution = 0.546 M
Converting the volume to liters:
14.60 mL * (1 L / 1000 mL) = 0.01460 L
Calculating the moles of HCl:
moles = 0.546 M * 0.01460 L = 0.00797 mol
Step 2: Use the balanced equation to determine the moles of MgCl2 produced
The balanced equation shows that the mole ratio between HCl and MgCl2 is 2:1. This means that for every 2 moles of HCl, 1 mole of MgCl2 is produced.
Since we know that 0.00797 moles of HCl are present, we can use the ratio to find the moles of MgCl2:
moles of MgCl2 = 0.00797 mol * (1 mol MgCl2 / 2 mol HCl) = 0.003985 mol
Step 3: Convert moles of MgCl2 to grams
To convert moles of MgCl2 to grams, we need to use the molar mass of MgCl2, which is the sum of the atomic masses of magnesium (Mg) and chlorine (Cl).
Molar mass of MgCl2:
Mg: 24.31 g/mol
Cl: 35.45 g/mol x 2 (since there are two chlorine atoms in MgCl2) = 70.90 g/mol
Total molar mass: 24.31 g/mol + 70.90 g/mol = 95.21 g/mol
Calculating the grams of MgCl2 produced:
grams = moles * molar mass
grams = 0.003985 mol * 95.21 g/mol = 0.3793 g
Therefore, approximately 0.3793 grams of MgCl2 can be produced from 14.60 mL of a 0.546M hydrogen chloride solution.