Sunday

December 21, 2014

December 21, 2014

Posted by **Amy** on Sunday, February 5, 2012 at 7:30pm.

(a.) If X is the width of the rectangular field, what are the maximum and minimum values of X?

(b.) What is the greatest number of square yards that can be enclosed in the two fields?

If you know how to answer even part of this question, that would be so helpful. Thank you so much :x :X

- Calculus -
**Anonymous**, Monday, February 6, 2012 at 12:18pmthe square has to be at least 10x10, using 40 yds of fence. That leaves 240 yds for the rectangle, so X+2X<=120, or X <= 40.

If X = 40, 2X = 80, so area = 3200

If 2X^2 = 800, X=20, so

20 <= X <= 40

As X increases from 20 to 40, the area increases from 800 to 3200

total area of square + rectangle can be as much as 3300

If the rectangle is 20x40, that uses up 120 yds of fence, leaving 220 for the square, or 55x55, with area 3025. Total area with maximum square is thus 3825.

**Answer this Question**

**Related Questions**

calculus - a farmer has a 2040 ft of fencing and wishes to fence off two ...

math - Flor is putting a fence around a field. The field is rectangular and ...

math help - ) Brian has 96 feet of fencing to enclose a rectangular space in his...

math - a school playground is in the shape of a rectangle 700 feet long and 200 ...

Calculus - you have 1000 yards of fencing and you plan to use the fencing to ...

Calculus - you have 1000 yards of fencing and you plan to use the fencing to ...

Calculus - A farmer has 120 meters of wire fencing to make enclosures for his ...

math - what is the area of a rectangle that is 3 yards wide by 8 yards long?

math - A football field is 120 yards long and 53 yards wide. How much fencing is...

Fher - a laundry room is shaped like a rectangle. the area of the room is 6 ...