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September 30, 2014

September 30, 2014

Posted by **tanya** on Sunday, February 5, 2012 at 5:44pm.

- verbal linear equations -
**Anonymous**, Sunday, February 5, 2012 at 6:44pmc = 2.75 + .85q

where

c = cost of ride

q = number of 1/4 miles driven

There are two ways you can tackle this. One is to figure the length of each ride:

23.15 = 2.75 + .85q

q = 24 (6 miles)

17.20 = 2.75 + .85q

q = 17 (4.25 miles)

So, the more expensive ride is 1.75 miles longer

------------------------------------

The other way is to see that once the initial charge is subtracted, the difference in cost is just .85 times the difference in quarter-miles:

(23.15-2.75)- (17.20-2.75) = .85d

Note how you don't even have to worry about the initial cost, since it cancels out when both charges are the same:

23.15-17.20 = .85d

5.95 = .85d

d = 7 quarter-miles

or, 1.75 miles difference

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