Posted by Shea on .
what is the maximum speed with which a car can round a turn of radius of 80.0m on a flat road if the coefficient of friction between tires and the road is .700?

physics 
bobpursley,
It matters if the road is banked. If unbanked, then force friction=centripetalForce
mg*mu=1/2 m v^2 / r
solve for v. 
physics 
Shea,
I don't have a mass.

physics 
Kole,
bobpursley's comment is on the right track, but the equation IS wrong. mg(a.k.a. normal force) x Coefficient of friction = (m x v^2)/r then the normal force breaks down into: m x a(a = 9.8 at sea level) the equation will then look as so: 9.8m x mu = (mv^2)/r the m's will cancel out getting rid of mass. solve from there

physics 
Phil,
Kole is right but how would you find velocity

physics 
A,
You solve for velocity