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March 25, 2017

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what is the maximum speed with which a car can round a turn of radius of 80.0m on a flat road if the coefficient of friction between tires and the road is .700?

  • physics - ,

    It matters if the road is banked. If unbanked, then force friction=centripetalForce

    mg*mu=1/2 m v^2 / r
    solve for v.

  • physics - ,

    I don't have a mass.

  • physics - ,

    bobpursley's comment is on the right track, but the equation IS wrong. mg(a.k.a. normal force) x Coefficient of friction = (m x v^2)/r then the normal force breaks down into: m x a(a = 9.8 at sea level) the equation will then look as so: 9.8m x mu = (mv^2)/r the m's will cancel out getting rid of mass. solve from there

  • physics - ,

    Kole is right but how would you find velocity

  • physics - ,

    You solve for velocity

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