The heat of vaporization of benzene, C6H6, is 30.8kJ/mol at its boiling point of 80.1 degrees celsius. How much energy in the form of heat is required to vaporize 102g of benzene at its boiling point?
I know that the answer is 24.2kJ but i am not sure how to get this.
how many moles of benzene is in 102 g? Figure that out.
Now, energy=30.8kJ/mol * number of moles
which is not your "answer", which is wrong.
I got 23.6. Is this correct?