ln p2/368.3 mm Hg = -24900 J/mol / 8.314 J/k mol [1/259.7K - 1/247.4K]

I am having trouble doing the mathto solve for p2.

The easy way is to calculate 1/259 = ? and 1/247 = ?, then subtract them and multiply that by -24900 and divide by 8.314.

That gives you an expression that looks like this.
ln p2/368.3 = a number
Then, making sure the number is punched into the calculator, hit the e^x button which then becomes p2/368.3 = the e^x value. Then solve for p2.

For some reason on my computer the answer that was posted was sort of cut of so I had a hard time reading it but when I did 1/259 - 1/247 I got -0.00018 then I multiplied by -24900 and divided by 8.314 and got 0.539.

Then I took the sqrt of this number and ended up with p2/368.3 = 0.734. Did I do this correctly so far?

To solve for p2, we can start by simplifying the equation step by step:

1. Start with the given equation: ln(p2/368.3 mmHg) = (-24900 J/mol / 8.314 J/K mol) * (1/259.7K - 1/247.4K)

2. Simplify the right side of the equation using the common denominator method:
= (-24900 J/mol / 8.314 J/K mol) * ([(247.4K - 259.7K) / (247.4K * 259.7K)])
= (-24900 J/mol / 8.314 J/K mol) * ([-12.3K / (247.4K * 259.7K)])
= -2.9959 x 10^-5 K^-1

3. Now, we have the simplified equation: ln(p2/368.3 mmHg) = -2.9959 x 10^-5 K^-1

4. To isolate p2, we can take the exponential of both sides of the equation, since ln is the inverse of the exponential function:
e^(ln(p2/368.3 mmHg)) = e^(-2.9959 x 10^-5 K^-1)

5. The exponential of ln cancels out, leaving us with:
p2/368.3 mmHg = e^(-2.9959 x 10^-5 K^-1)

6. Finally, to solve for p2, multiply both sides of the equation by 368.3 mmHg:
p2 = e^(-2.9959 x 10^-5 K^-1) * 368.3 mmHg

Now, you can use a calculator to calculate the value of e^(-2.9959 x 10^-5 K^-1), and then multiply it by 368.3 mmHg to find the value of p2.