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July 24, 2014

July 24, 2014

Posted by **kulani** on Sunday, February 5, 2012 at 9:04am.

- physics -
**drwls**, Sunday, February 5, 2012 at 9:26amYou have more information than you need to answer this question. The time to fall does not depend upon the mass, or how high it bounces, or the contact time. The "fall time" is simply

t = sqrt(2H/g)= 2.86 seconds

Are there other parts of the question that require the other information (such as the average force on the ground during a bounce)?

- physics -
**kulani**, Sunday, February 5, 2012 at 11:07am22.98

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