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March 27, 2017

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(a) How much heat in kcal must be provided for a 0.853 kg block of lead to raise the
temperature of 0.015 kg block of ice from -5ºC to 0ºC? (b) How much heat in kcal must be
provided for a 0.853 kg block of lead to melt a 0.015 kg block of ice from at 0ºC? (c) How
much heat in kcal must be provided for a 0.853 kg block of lead to raise the temperature of
0.015 kg of liquid water from 0ºC to 5ºC? (d) What is the total amount of heat in kcal needed
for the whole process? (e) To what temperature must a 0.853 kg block of lead be heated in
order to complete this task? (specific heat for lead = 0.0305 kg/kcal*Cº)(Assume that there is
no heat lost to the surroundings.)

  • Physics - ,

    (a) You need the specific heat of ice, C(ice). Look it up.
    Then use Q1 = M*C(ice)*deltaT
    deltaT = 5C in this case
    M = 0.015 kg
    (b) You need the heat of fusion of ice, H. It is 80 kcal/kg
    Then use
    Q2 = M*H
    (c) Use the specific heat of water,
    C(liq)= 1.00 kcal/kg*C
    Then use Q3 = M*Cliq*deltaT
    deltaT = 5C in this case
    (d) Add up Qtotal = Q1 + Q2 + Q3
    (e) M(lead)*C(lead)*(T - 5) = Qtotal
    They tell you the values of M(lead) and C(lead)
    Solve for T

  • Physics - ,

    Thank you for your help!

  • Physics - ,

    You're welcome!

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