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Write an equation of the line containing the given point and parallel to the given line. (6,-7):9x-8y=3 The equation of the line is y=

  • math - ,

    Solve for the slope of the 9x-8y=3. You get y= 9/8x - 3/8. So your slope is 9/8. Because the line is parallel. You then use point slope formula to get equation of line in y=mx+b form.(slope form).
    So y-y1=m(x-x1)
    y-(-7)=9/8(x-6)
    y+7=9/8(x-6)
    So y=9/8x -55/4

    I did the math in my head so double check the arithmetic.

  • math - ,

    First, get the slope of the equation by writing it in the form y=mx+b.
    given: 9x-8y=3
    (-8y=-9x+3)/-8
    y=8/9x-3/8
    slope=8/9

    use point-slope form
    m=8/9 and (6,-7)
    y-(-7)=8/9(x-6)
    y+7=8/9x-48/9
    y=8/9x-48/9-7

    Final answer: y=8/9x - 37/3

  • math - ,

    sorry i got a wrong slope... this is the correct answer...

    9x-8y=3
    (-8y=-9x+3)/-8
    y=9/8x - 3/8
    m=9/8

    given: m= 9/8 and (6,-7)
    y-(-7)=9/8(x-6)
    y+7=9/8x-27/4
    y=9/8x-27/4-7

    y=9/8x-55/4 final answer...

  • math - ,

    9x-8y=-2

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