Posted by **Kristi** on Sunday, February 5, 2012 at 6:35am.

Write an equation of the line containing the given point and parallel to the given line. (6,-7):9x-8y=3 The equation of the line is y=

- math -
**Declan**, Sunday, February 5, 2012 at 6:56am
Solve for the slope of the 9x-8y=3. You get y= 9/8x - 3/8. So your slope is 9/8. Because the line is parallel. You then use point slope formula to get equation of line in y=mx+b form.(slope form).

So y-y1=m(x-x1)

y-(-7)=9/8(x-6)

y+7=9/8(x-6)

So y=9/8x -55/4

I did the math in my head so double check the arithmetic.

- math -
**PDF**, Sunday, February 5, 2012 at 7:06am
First, get the slope of the equation by writing it in the form y=mx+b.

given: 9x-8y=3

(-8y=-9x+3)/-8

y=8/9x-3/8

slope=8/9

use point-slope form

m=8/9 and (6,-7)

y-(-7)=8/9(x-6)

y+7=8/9x-48/9

y=8/9x-48/9-7

Final answer: y=8/9x - 37/3

- math -
**PDF**, Sunday, February 5, 2012 at 7:16am
sorry i got a wrong slope... this is the correct answer...

9x-8y=3

(-8y=-9x+3)/-8

y=9/8x - 3/8

m=9/8

given: m= 9/8 and (6,-7)

y-(-7)=9/8(x-6)

y+7=9/8x-27/4

y=9/8x-27/4-7

y=9/8x-55/4 final answer...

- math -
**lisa**, Sunday, May 27, 2012 at 7:01pm
9x-8y=-2

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