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A diver running 1.69 m/s dives out horizontally from the edge of a vertical cliff and 3.11 s later reaches the water below. How high was the cliff, and how far from the base did the diver hit the water?

  • Physics - ,

    h = .5 g t^2
    h= .49 (3.11)^2

    d = 1.69 t

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