Posted by **Stacy** on Sunday, February 5, 2012 at 12:42am.

A hunter aims directly at a target (on the same level) 61.0 m away. If the bullet leaves the gun at a speed of 176 m/s, by how much will it miss the target?

At what angle should the gun be aimed so as to hit the target?

- Physics -
**Henry**, Monday, February 6, 2012 at 4:37pm
Dx = V*t,

t = Dx/V = 61 / 176 = 0.347 s.

Dy = 0.5g*t^2 = 4.9*(0.347)^2=0.589 m.=

Miss distance.

- Physics -
**Henry**, Monday, February 6, 2012 at 4:55pm
b. Dx = Vo^2*sin(2A)/g = 61 m,

(176)^2*sin(2A)/9.8 = 61,

Divide both sides by (176)^2:

sin(2A) / 9.8 = 1.9693*!0^-3,

Multiply both sides by 9.8:

sin(2A) = 0.0193,

2A = 1.1058,

A = 0.553 Deg.

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