Posted by Anonymous on .
A race driver has a pit stop to refuel. After refueling, he starts from rest and leaves the pit area with an acceleration whose magnitude is 5.5 m/s^2; after 3.6 s he enters the main speedway. At the same instant, another car on the speedway and traveling at a constant velocity of 71.7 m/s overtakes and passes the entering car. The entering car maintains its acceleration. How much time is required for the entering car to catch up with the other car?

trig 
Henry,
Vo = at = 5.5*3.6 = 19.8 m/s.
19.8*t + 0.5*5.5*t^2 = 71.7t,
2.75t^2 + 19.8t  71.7t = 0,
2.75t^2  49.15t = 0.
Use Quadratic Formula and get:
17.9 s.