I tried using my calculator and punching in the choices to figure out what x is and none of them equaled -10 so idk what i did wrong
Find the value of x that will make the following numerical expression equal to − 10 .
-5^2+(x+2)/-4-(-6)
(a)−1 (b)−3 (c)2 (d)1 (e)3
(-5^2+(x+2))/-4-(-6) = -10
(-25 + (x+2))/(-4+6) = -10
(-25 + (x+2))/2 = -10
-25 + x + 2 = -20
-23 + x = -20
x = -20 + 23
x = 3
so, it's letter (E).
hope this helps~ :)
To find the value of x that will make the expression equal to -10, let's break down the steps.
The given expression is:
-5^2 + (x+2)/-4 - (-6)
1. First, let's simplify the exponent -5^2. From the order of operations (PEMDAS/BODMAS), exponentiation should be done before any other operations. So -5^2 means (-5) * (-5), which gives us 25.
Now our expression becomes:
25 + (x+2)/-4 - (-6)
2. Next, let's simplify the expression within the parentheses. (x + 2) remains the same.
Now our expression becomes:
25 + (x + 2)/-4 - (-6)
3. Now, let's simplify the expression with subtraction:
-(-6) equals +6. So our expression becomes:
25 + (x + 2)/-4 + 6
4. Let's deal with the fraction (x + 2)/-4. To simplify this, multiply the numerator by -1 and denominator by -1 to change the division into multiplication:
(x + 2)/-4 becomes -(x + 2)/4.
Our expression now looks like:
25 - (x + 2)/4 + 6
5. Combine all the terms:
25 - (x + 2)/4 + 6 can be simplified to (25 + 6 - (x + 2)/4).
6. From here, we have:
(31 - (x + 2)/4) = -10
To find the value of x, we need to isolate it on one side of the equation. Let's start by subtracting 31 from both sides:
- (x + 2)/4 = -41
To get rid of the fraction, we'll multiply both sides of the equation by -4:
x + 2 = (-41) * (-4)
Multiply the two numbers on the right side:
x + 2 = 164
Finally, subtract 2 from both sides to solve for x:
x = 164 - 2
Simplifying further:
x = 162
Therefore, the value of x that makes the numerical expression equal to -10 is 162.
It seems like you might have made an error while entering the expression into your calculator. Make sure to use parentheses correctly, especially with negative numbers and exponents, to ensure accurate calculations.