Posted by velagala on Saturday, February 4, 2012 at 11:05am.
8
The fact that it is a 13 by 13 is irrelevant.
Draw your 2 diagonals and count the number of points you see. Label the points A, B, C, D, and E, where E is the intersection of the diagonals.
A triangle is formed by connecting any 3 points, unless the 3 points lie in a straight line
e.g. ABC will form a triangle
AED will form a triangle , but AEC will not
So it becomes the number of ways we can choose 3 of the 5 points, which is
C(5,3) = 5!/(3!2!) = 10
but that would include AEC and BED, which form a straight line,
so there are 10-2 or 8 triangles
You could use the above reasoning for any polygon
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