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April 20, 2014

Homework Help: chemistry

Posted by don on Friday, February 3, 2012 at 9:01pm.

(100g)(.473J/g°C)(x-62°C) =-(500g)(4.184J/g°C)(x-22°C)

Q = mass•specific heat•change in temperature

Can someone show me how to solve this so i can teach myself before my test on Monday
..thanks for your time

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