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Chemistry

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Find the value of delta H net for the following equation:

SnBr2(s) + TiCl4(l) -> TiBr2(s) + SnCl4(l)

I know that I already posted this once but I am still lost on what to do.

I know that TiCl4=-804.2 and SnCl4=-511.3 but I thought that the values for SnBr2 is 0 as well as for TiBr2.



Chemistry - DrBob222, Wednesday, February 1, 2012 at 10:00pm
SnBr2 is not zero.
TiBr2 is not zero.
I don't know what they are but they aren't zero. The only DHf values that are zero are elements which appear in an equation in their normal state. O2(g), H2(g), etc.



Chemistry - Hannah, Thursday, February 2, 2012 at 11:55pm
How should I go about solving this problem? Am I missing information?

  • Chemistry - ,

    I don't know what to tell you. I can't find that in any of the texts I have nor can I find it on the web. I'm sure it's somewhere on the web; I've just not found it.

  • Chemistry - ,

    Ok well thank you for trying!

  • Chemistry - ,

    I don't know if this will help but I realized there was more information for the problem.

    1) SnCl2(s) + TiBr2(s) -> SnBr2(s) + Ticl2(s) Delta H=+4.2

    2) SnCl2(s) + Cl2(g) -> TiCl4(l) deltaH=-195

    3) TiCl2(s) + Cl2(g) ->TiCl4(l) deltaH=-273

    SnCl2(s) + Cl2(g) -> SnCl4(l) deltaH=-195

    TiCl4(l) -> TiCl2(s) + Cl2(g) deltaH=+273

    SnCl2(s) + TiCl4(l) -> TiCl2(s) + SnCl4(l) deltaH net = 78

    The directions for the original question that I posted said to use the reactions above to find the net value for the new equation.

  • Chemistry - ,

    Hannah, will you PLEASE check your post. I've already spent (wasted may be a better word) hours on this thing only to find that you didn't post the entire problem. I MAY (and I emphasize MAY) be able to do something with that; however, I do not believe equation 2. Finally you don't have any units. Start over, post the entire problem and question (as a new post), and all of the data, including units. Proof it thoroughly before posting. I assume "net value" means to find the delta H for the reaction. Is that right?

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