physics
posted by Cody on .
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A quarterback claims that he can throw the football a horizontal distance of 196.6 m (215 yd). Furthermore, he claims that he can do this by launching the ball at the relatively low angle of 30° above the horizontal. To evaluate his claim, determine the speed with which this quarterback must throw the ball.

Given a kickoff of velocity v at angle a, the range is given by
R = v^2 sin(2a)/g
196.6 = v^2 * .866 / 9.8
v^2 = 2224.8
v = 47.17m/s
v =~ 170km/hr, not too likely, especially since no quarterback would be discussing distances in meters!