Math, Please Help!!!
posted by Desperate!!!! on .
1. The problem statement, all variables and given/known data
a ball is thrown straight down from the top of a 220 feet building with an initital velocity of 22ft/s. What is the velocity of the ball after 3 seconds? What is the velocity of the ball after falling 108 feet?
2. Relevant equations
s(t) = 16t^2 + Vi(t) + si vi = initial velocity, si = initial position
3. The attempt at a solution
s(t) = 16t^2 +Vi(t) +si
= 16t^2  22ft/s + 200ft
V(t) = 32(t)  22ft/s
V(3) = 96 ft/s  22ft/s = 118 ft/s
I can seem to figure out how to determine the velocity of the ball after it has dropped 108ft.
I should be able to do this, but i'm missing something, somewhere on what should be pretty basic.
Thanks for any guidance!

done under your previous post as Audrey
http://www.jiskha.com/display.cgi?id=1328273218