Posted by sally on Friday, February 3, 2012 at 2:54am.
The average speed of the train, from the time deceleration begins until the last car passes, is
(80.1 + 16.9)/2 = 48.5 m/s.
The train moves 400 m during that time, so it took 0.4 km/48.5 km = 8.247*10^-3 h to leave the crossing. That is 29.7 seconds
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