How many grams of sulfur (S8) must be dissolved in 100.0 naphthalene (C10H8) to make a 0.13 solution?
answer in grams.
To find out how many grams of sulfur (S8) need to be dissolved in 100.0 grams of naphthalene (C10H8) to make a 0.13 solution, we need to know the molar mass of both sulfur and naphthalene.
The molar mass of sulfur (S8) is generally 32.08 grams/mole.
The molar mass of naphthalene (C10H8) can be calculated as follows:
Molar mass of carbon (C) = 12.01 grams/mole
Molar mass of hydrogen (H) = 1.01 grams/mole
Adding the molar masses of all the atoms in naphthalene,
10 x (12.01 grams/mole) + 8 x (1.01 grams/mole) = 128.18 grams/mole
To make a 0.13 solution, we need 0.13 moles of sulfur for every 1 liter (1000 grams) of naphthalene.
Now, let's calculate how many moles of sulfur we need for 100.0 grams of naphthalene:
100.0 grams naphthalene x (1 mole naphthalene / 128.18 grams naphthalene) = 0.780 moles naphthalene
Since the molar ratio of sulfur to naphthalene is 8:1 (from the formula S8), we can calculate the moles of sulfur required:
0.780 moles naphthalene x (8 moles sulfur / 1 mole naphthalene) = 6.24 moles sulfur
Finally, let's calculate the grams of sulfur needed for 6.24 moles:
6.24 moles sulfur x (32.08 grams sulfur / 1 mole sulfur) = 200.42 grams sulfur
Therefore, approximately 200.42 grams of sulfur (S8) must be dissolved in 100.0 grams of naphthalene (C10H8) to make a 0.13 solution.
To find the number of grams of sulfur (S8) needed to make a 0.13 M solution in 100.0 g of naphthalene (C10H8), we need to follow a few steps.
Step 1: Determine the molar mass of sulfur (S8) and naphthalene (C10H8).
- The molar mass of sulfur (S8) can be calculated by multiplying the atomic mass of sulfur (S) by 8 since there are 8 sulfur atoms in one molecule of S8.
- The atomic mass of sulfur (S) is approximately 32.06 g/mol.
- So, the molar mass of sulfur (S8) = 32.06 g/mol × 8 = 256.48 g/mol.
- The molar mass of naphthalene (C10H8) can be calculated by adding the atomic masses of carbon (C) and hydrogen (H).
- The atomic mass of carbon (C) is approximately 12.01 g/mol, and the atomic mass of hydrogen (H) is approximately 1.01 g/mol.
- So, the molar mass of naphthalene (C10H8) = (12.01 g/mol × 10) + (1.01 g/mol × 8) = 128.18 g/mol.
Step 2: Convert the given concentration to moles.
- To convert the concentration to moles, we need to multiply the molarity (0.13 M) by the volume (in liters) of the solution.
- However, the volume of the solution is not provided in the question, so we cannot directly calculate the number of moles.
Step 3: Calculate the number of moles of naphthalene (C10H8) using its mass.
- The mass of naphthalene given is 100.0 g.
Step 4: Determine the number of moles of sulfur (S8) using mole ratios.
- From the balanced chemical equation, we know that one mole of sulfur reacts with one mole of naphthalene (C10H8) to produce one mole of S8.
- Since the molar ratio between sulfur (S8) and naphthalene (C10H8) is 1:1, the moles of sulfur (S8) needed will be equal to the moles of naphthalene (C10H8).
Step 5: Calculate the mass of sulfur (S8) using its molar mass and the number of moles obtained from step 4.
- Multiply the number of moles of sulfur (S8) by its molar mass (256.48 g/mol) to get the mass of sulfur (S8) required in grams.
Steps 1 to 5 are required to calculate the number of grams of sulfur (S8) needed to make a 0.13 M solution in 100.0 g of naphthalene (C10H8).
You didn't use any units. I assume 0.13 is molar and I assume 100 is mL (which in the equation below will be 0.1 L)
M = moles/L.
You have M and L. solve for moles.
Then moles = grams/molar mass. Solve for grams.