the ratio of the number of coins Azam had to the number of coins Eddie had was 3:7.Eddie gave 42 coins to Azam and they ended up having the same number of coins.how many coins did each person have at first? pls sh

orginal:

number of coins for Azam = 3x
number of coins for Eddie = 7x

Eddie gave 42 coins to Azam
Azam now has 3x + 42
Eddie now has 7x - 42

but 7x - 42 = 3x + 42
4x = 84
x = 21

So at first
Azam had 3(21) or 63
Eddie had 7(21) = 147

Well, let's use our mathematical clown logic to solve this.

If we assume that the number of coins Azam had is represented by 3x, and the number of coins Eddie had is represented by 7x, we can set up an equation:

3x + 42 = 7x

Now, let's find out the value of x by solving this equation:

42 = 4x

Divide 42 by 4 and we get:

x = 10.5

So, plug this value of x back into our original equation to find the total number of coins each person had:

Azam: 3x = 3 * 10.5 = 31.5 coins
Eddie: 7x = 7 * 10.5 = 73.5 coins

But, wait! We can't have halves of coins, that's just silly! So, let's round down Azam's coins to 31 and round up Eddie's coins to 74.

Therefore, at first, Azam had 31 coins, and Eddie had 74 coins.

Let's assume that the number of coins Azam had initially is represented by "3x" and the number of coins Eddie had initially is represented by "7x".

According to the problem, Eddie gave 42 coins to Azam. After receiving the 42 coins, Azam and Eddie had an equal number of coins. So, we can create the following equation:

7x - 42 = 3x + 42

To solve this equation, let's combine like terms:

7x - 3x = 42 + 42
4x = 84

Next, divide both sides of the equation by 4:

4x/4 = 84/4
x = 21

Now that we know the value of x, we can calculate the number of coins Azam and Eddie had initially:

Azam had 3x coins = 3 * 21 = 63 coins
Eddie had 7x coins = 7 * 21 = 147 coins

Therefore, Azam initially had 63 coins, and Eddie initially had 147 coins.

To solve this problem, let's break it down step by step:

1. Let's assume that the initial number of coins Azam had is represented by "3x" (where x is a positive integer), and the initial number of coins Eddie had is represented by "7x".

2. According to the problem, Eddie gave 42 coins to Azam. So we can set up an equation: (7x - 42) = (3x + 42), as both individuals ended up having the same number of coins.

3. Solving the equation above will give us the initial number of coins for each person:

Distributing the numbers:
7x - 42 = 3x + 42

Collecting like terms:
7x - 3x = 42 + 42

Simplifying the equation:
4x = 84

Dividing both sides by 4:
x = 21

4. Now that we know "x" is equal to 21, we can find the number of coins each person had at first:

For Azam:
Initial number of coins = 3x = 3 * 21 = 63 coins

For Eddie:
Initial number of coins = 7x = 7 * 21 = 147 coins

Therefore, Azam initially had 63 coins, and Eddie initially had 147 coins.