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November 28, 2014

November 28, 2014

Posted by **Please, Please Help!** on Thursday, February 2, 2012 at 10:52pm.

S(t) = 68 − 20 log (t + 1), t ¡Ý 0.

What was the average score when they initially took the test, t = 0?

Round your answer to a whole percent, if necessary.a)Answer:

Show your work in this space:

What was the average score after 4 months? after 24 months?

Round your answers to two decimal places.b)Answer:Show your work in this space:

After what time t was the average score 50%?Round your answe

- college algebra -
**Reiny**, Friday, February 3, 2012 at 8:19amwhen t = 0

S(0) = 68 - 20log(1) = 68

when t= 4

S(4) = 68 - 20log(5) = 54.02... or 54

etc.

for score to be 50

50 = 68 - 20log(t+1)

log(t+1) = 18/20 = .9

t+1 = 10^.9

t = 10^.9 - 1 months

= 6.943 or appr. 7 months

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