Posted by **Marko** on Thursday, February 2, 2012 at 10:20pm.

At. The first meeting of a chess club the 9 members decide to have a tournament in which each player plays a game against every other player. How many games will there be??

Can you help me figure this out ?

- Math word problem -
**Reiny**, Thursday, February 2, 2012 at 10:32pm
Each of the 9 players would play against 8 others, that would give us 9x8 or 72

BUT, wouldn't that include such games as

A vs B and B vs A, which is the same game.

So we have to divide by 2 to get all those duplications taken out

number of games = 72/2 = 36

In mathematical symbols that would be

C(9,2) = 9!/(2!7!) = 36

- Math word problem -
**Anonymous**, Friday, February 3, 2012 at 11:54am
John has five more than twice the number of CDs that Kate has. Together they have 100 CDs

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