Thursday

October 2, 2014

October 2, 2014

Posted by **kayla** on Thursday, February 2, 2012 at 7:27pm.

(b) Calculate the horizontal retarding force on the mower

(c) Calculate the normal force exerted vertically upward on the mower by the ground.

(d) Calculate the force the person must exert on the lawn mower to accelerate it from rest to 1.3 m/s in 2.0 seconds (assuming the same retarding force).

- physics -
**Henry**, Saturday, February 4, 2012 at 6:25pmWm = mg = 17kg * 9.8N/kg = 166.6 N. =

Wt. of mower.

Fm = 166.6 N @ 0 Deg. = Force of mower.

Fp = 166.6*sin(0) = 0. = Force parallel

to gnd.

Fv = 166.6*cos(0) = 166.6 N. = Force

perpendicular to Gnd. = Normal.

b. Fn = Fap-Fp-Fr = 0,

74*cos48-0-Fr = 0,

49.52-Fr = 0,

Fr = 49.52 N. = Retarding force.

c. Fv = mg = 166.6 N.

d. a = (Vf-Vo)/t,

a = (1.3-0) / 2 = 0.65 m/s^2.

Fcos48-Fr = ma,

Fcos48-49.52 = 17*0.65 = 11.05,

Fcos48 = 11.05+49.52 = 60.57,

F = 60.57 / cos48 = 90.5 N.

**Answer this Question**

**Related Questions**

physics - forces - A person pushes a 16.0 kg lawn mower at constant speed with a...

Physics - A person pushes a 11.0 kg lawn mower at constant speed with a force of...

physics - A person pushes a 14.0-kg lawn mower at constant speed with a force of...

physics - A person pushes a 10.0 kg lawn mower at constant speed with a force of...

physics - A person pushes a 11.0 kg lawn mower at constant speed with a force of...

Ap physics - A person pushes a 15.0 kg lawn mower at constant speed with a force...

12th grade Physics - A boy pushes a lawn mower with a mas of 17.9 kg starting ...

college math - A lawn mower handle makes an angle of 60° with the ground. A ...

physics - A person pushes a 14.5 kg lawnmower at constant speed with a force of ...

Physics - 1)The x- and y-components of a velocity vector of 100 N at 240 degrees...