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January 28, 2015

January 28, 2015

Posted by **kayla** on Thursday, February 2, 2012 at 7:27pm.

(b) Calculate the horizontal retarding force on the mower

(c) Calculate the normal force exerted vertically upward on the mower by the ground.

(d) Calculate the force the person must exert on the lawn mower to accelerate it from rest to 1.3 m/s in 2.0 seconds (assuming the same retarding force).

- physics -
**Henry**, Saturday, February 4, 2012 at 6:25pmWm = mg = 17kg * 9.8N/kg = 166.6 N. =

Wt. of mower.

Fm = 166.6 N @ 0 Deg. = Force of mower.

Fp = 166.6*sin(0) = 0. = Force parallel

to gnd.

Fv = 166.6*cos(0) = 166.6 N. = Force

perpendicular to Gnd. = Normal.

b. Fn = Fap-Fp-Fr = 0,

74*cos48-0-Fr = 0,

49.52-Fr = 0,

Fr = 49.52 N. = Retarding force.

c. Fv = mg = 166.6 N.

d. a = (Vf-Vo)/t,

a = (1.3-0) / 2 = 0.65 m/s^2.

Fcos48-Fr = ma,

Fcos48-49.52 = 17*0.65 = 11.05,

Fcos48 = 11.05+49.52 = 60.57,

F = 60.57 / cos48 = 90.5 N.

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