An electron is released from rest in a uniform electric field of magnitude 2.00 x 10e4 N/C. Calculate the acceleration of the electron (neglect gravitation).
acceleration = e*E/m
e and m are the elctron charge and mass, respectively. E is the electric field strength, in N/C units.
Now do the calculation
3.51*10^15
To calculate the acceleration of an electron released in a uniform electric field, we can use the equation for the electric force experienced by a charged particle:
F = qE
Where:
F is the electric force on the electron,
q is the charge of the electron (1.6 x 10^-19 C),
and E is the electric field strength (2.00 x 10^4 N/C).
We know that force (F) is related to mass (m) and acceleration (a) by Newton's second law:
F = ma
By substituting the expressions for the electric force and rearranging the equation, we can solve for acceleration:
ma = qE
a = (qE) / m
Now, plug in the values into the equation:
a = [(1.6 x 10^-19 C) * (2.00 x 10^4 N/C)] / (mass of the electron)
The mass of the electron is approximately 9.11 x 10^-31 kg.
a = [(1.6 x 10^-19 C) * (2.00 x 10^4 N/C)] / (9.11 x 10^-31 kg)
Now, calculate the value:
a = 3.51 x 10^14 m/s^2
Therefore, the acceleration of the electron in the uniform electric field is approximately 3.51 x 10^14 m/s^2.