A box contains 3 red marbles, 6 blue marbles, and 1 white marble. The marble are selected at random, one at a time, and are not replaced. Find the probability.
P(blue and red)
Please help me
P(blue) = 6/10 = 3/5 = .6
Once blue is chosen, P(red) = 3/9 = 1/3 = .333
Probability of both/all events occurring is found by multiplying the probability of the individual events.
To find the probability of selecting a blue and a red marble from the box, we first need to find the total number of possible outcomes and the number of favorable outcomes.
Total number of possible outcomes:
To calculate this, we need to determine the total number of marbles in the box. There are 3 red marbles, 6 blue marbles, and 1 white marble, so the total number of marbles is 3 + 6 + 1 = 10.
Since we are selecting the marbles without replacement, the total number of possible outcomes decreases by one each time we choose a marble.
Number of favorable outcomes:
We want to select one blue marble and one red marble.
The number of ways to select one blue marble from the 6 available blue marbles is 6.
After selecting the blue marble, there are 3 red marbles remaining, so the number of ways to select one red marble is 3.
Now, we can calculate the probability:
Probability = Number of favorable outcomes / Total number of possible outcomes
P(blue and red) = (6 blue marbles * 3 red marbles) / (10 total marbles)
P(blue and red) = 18 / 10
Simplifying, we get:
P(blue and red) = 9/5