A grocery store wants to make a mixture of nuts consisting of cashews and pecans. The cashews sell for $4 per pound while the pecans sell for $10 a pound. How many pounds of each nut must be mixed to produce a 6 pound mixture that sells for $8 per pound.

total cost is

4c + 10(6-c) = 8*6
4c + 60 - 10c = 48
6c = 12
c = 2
so p = 4

Note that $8 is 2/3 of the way from $4 to $10, and so p is 2/3 of the final mix.

If I had 40 pounds of pecans and each pound is $2.50 how much money will I have

A deli charges $2.50 for the first pound of meat, and $.75 for each additional pound.this is represented by the equation c=2.50+0.75,how many pounds I buy

To solve this problem, we need to use a system of equations. Let's denote the number of pounds of cashews as C, and the number of pounds of pecans as P.

1. The first equation we can set up is based on the total weight of the mixture:
C + P = 6

2. The second equation relates to the cost per pound of the mixture:
(4C + 10P) / 6 = 8

To solve this system of equations, we can use substitution or elimination method:

Using substitution method:
- Solve the first equation for C: C = 6 - P
- Substitute this value into the second equation:
(4(6 - P) + 10P) / 6 = 8

Now, solve for P:
(24 - 4P + 10P) / 6 = 8
(6P + 24) / 6 = 8
6P + 24 = 48
6P = 48 - 24
6P = 24
P = 24 / 6
P = 4

Now, substitute the value of P back into the first equation to find C:
C + 4 = 6
C = 6 - 4
C = 2

So, you would need 2 pounds of cashews and 4 pounds of pecans to produce a 6 pound mixture that sells for $8 per pound.