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March 30, 2017

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Find two consecutive positive integers such that the square of the smaller increased by 4 times the larger is 64.

  • Math - ,

    let the two numbers be x and x+1
    x^2 + 4(x+1) = 64

    x^2 + 4x + 4 - 64=0
    x^2 + 4x - 60 = 0
    (x+10)(x-6) = 0
    x = -10 or x = 6
    but you wanted only positive integers, so x = 6

    the two numbers are 6 and 7

    check:
    What is 6^2 + 4(7) ??

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