Posted by **Yolie** on Thursday, February 2, 2012 at 2:56am.

Solve the equation. Check for extraneous solutions.

ln x + ln(x-2) = 1

- Alg 2 -
**Reiny**, Thursday, February 2, 2012 at 7:33am
lnx + ln(x-2) = 1 , where x>2

ln(x(x-2)) = 1

x^2 - 2x = e^1

x^2 - 2x + 1 = e+1 , ( I completed the square)

(x-1)^2 = e+1

x - 1 = ± √(e+1)

x = 1 ± √(e+1)

but x > 2 , so

x = 1 + √(e+1)

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