Posted by Yolie on Thursday, February 2, 2012 at 2:56am.
Solve the equation. Check for extraneous solutions.
ln x + ln(x2) = 1

Alg 2  Reiny, Thursday, February 2, 2012 at 7:33am
lnx + ln(x2) = 1 , where x>2
ln(x(x2)) = 1
x^2  2x = e^1
x^2  2x + 1 = e+1 , ( I completed the square)
(x1)^2 = e+1
x  1 = ± √(e+1)
x = 1 ± √(e+1)
but x > 2 , so
x = 1 + √(e+1)