Posted by **lola** on Wednesday, February 1, 2012 at 4:55pm.

Use L’Hopital’s rule to find the limit of this sequence

(n^100)/(e^n)

...If you do L'Hop. Rule it would take forever, right? You would always get an (e^n) at the bottom and will have to use the L'Hop. rule 100 times to find the limit...100*n^99, 9900n^98, and etc.

Is there a shortcut to find the limit?

Or, am I doing something way wrong?

calc - Reiny, Wednesday, February 1, 2012 at 12:06pm

You didn't say what the aprroach value is for n

is n---> 0 ?

lim n^100/e^n)

= lim (100n^99)/(e^n)

= lim (9900n^98) / e^n

= ...

= lim (huge n^1)/e^n

= lim (more huge )/e^n

= lim (0/e^n)

= 0/1

= 0

calc - lola, Wednesday, February 1, 2012 at 12:29pm

what if n approaches infinity?

- calc -
**Steve**, Wednesday, February 1, 2012 at 5:26pm
This shows that any polynomial, no matter how high the degree, grows more slowly than any exponential function of a base >1.

Repeated application of L’Hopital’s Rule just reduces the degree of the numerator by 1, and when you get to a constant, one more application reduces the numerator to ZERO. The denominator is still e^x.

- calc -
**lola**, Wednesday, February 1, 2012 at 6:06pm
so the limit is zero

- calc -
**lola**, Wednesday, February 1, 2012 at 6:25pm
is the limit zero?

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